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5x^2-5x-450=0
a = 5; b = -5; c = -450;
Δ = b2-4ac
Δ = -52-4·5·(-450)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9025}=95$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-95}{2*5}=\frac{-90}{10} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+95}{2*5}=\frac{100}{10} =10 $
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